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Steam expands in a turbine from 4 MPa and 500 C and 0.5 MPa and 250C at a rate of 1350 kg/h. Heat is lost from the turbine at a rate of 25 kJ/s during the process. The power output of the turbine is

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onyebuchinnaji

The power output of the turbine during the steam expansion process is determined as 157 kW.

Power output of the turbine

The power output of the turbine is calculated as follows;

P(out) = m'(h₁ - h₂) - Q(loss)

where;

  • m' is the mass flow rate (kg/s)

m' = (1350 kg)/(3600 s)

m' = 0.375 kg/s

From steam table for  superheated water,

  • h₁ at  500 ⁰C and 4 MPa  = 3446 kJ/kg
  • h₂ at 250 ⁰C and 0.5 MPa = 2961 kJ/kg

P(out) = m'(h₁ - h₂) - Q(loss)

P(out) = 0.375(3446 - 2961) - 25 kJ/s

P(out) =  156.88 kJ/s = 156.88 kW ≈ 157 kW

Learn more about power output here: https://brainly.com/question/20038729

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